On Arithmetic
Series and Geometric Series |
In proving the formulas of the sums
of an arithmetic or geometric sequences, the following
non-conventional methods worth studying : |
Arithmetic series
Let the arithmetic series be
a1, a2, …., an with a common difference, d. The arithmetic mean of the
first n terms is equal to the arithmetic mean of the first and last terms. That is: |
Arithmetic series
Let the arithmetic series be
a1, a2, …., an with a common difference, d. (Please investigate the reasoning for equation (2) below) S(n) = a1
+ (a1 + d) + (a1
+ 2d) +
……. +
[a1 +
(n-1)d] (1) S(n) = an
+ (an -
d) + (an - 2d)
+ ……. + [an
- (n-1)d] (2) |
Geometric series
Let the geometric series be
a1, a2, …., an with a common ratio, r. (r ¹ 1) S(n)
= a1
+ a1r + a1r2 + …. + a1rn-1 S(n-1)
= a1 + a1r
+ a1r2 + …. + a1rn-2 We can see that : S(n)
- S(n-1) = a1rn-1 (1) S(n)
– r S(n-1) = a1 (2) The above is a simultaneous system of
equations with 2 unknowns
S(n) and S(n-1). We can then solve for
S(n). Consider (2) –
r(1), we
get for r ¹ 1, |
Geometric series
Let
the geometric series be a1,
a2, …., an
with a common ratio,
r. (r ¹ 1) Then, By the Equal Ratio Theorem, rS(n)
– a1rn = S(n) – a1 S(n)
[1 – r] = a1 [1 – rn] |
Difference Method
For more mathematical
mature readers, the employment of
first order difference method We define the difference
operator: Df(x) = f(x + 1) – f(x) Then we have the following
elementary properties: 1. For
any constant k , D k f(x) = k f(x
+ 1) – k f(x) = k [f(x + 1) – f(x)] 2. Now, Darx-1 = arx – arx-1 = arx-1 (r – 1) If r ¹ 1, then we get ,
by property (1) above. Using property (2), we
have: Writing the summation in
full, we finally get: Readers interested in learning more on difference method may consult some advanced algebra books. |